question_answer

Directions: Q. 1 to 5

Vijay is trying to find the average height of a tower near his house.

He is using the properties of similar triangles. The height of Vijay's house, if 20 m when Vijay's house casts a shadow 10m long on the ground.

At the same time, the tower casts a shadow 50 m long on the ground and the house of Ajay casts 20 m shadow on the ground.

Based on the above information, answer the following questions

What is the height of the tower?

A) 20m

B) 50m

C) 100m

D) 200m

Correct Answer: C

Solution :

Let CD = h m be the height of the tower. Let BE = 20 m be the height of Vijay's house and GF be the height of Ajay's house,

\[\Delta ACD\tilde{\ }ABE\]

\[\therefore \frac{AC}{AB}=\frac{CD}{EB}\]

\[\Rightarrow \frac{50}{10}=\frac{h}{20}\]

\[\Rightarrow h=100m\]