A) High bond energy of Xe - F Bond
B) Low bond energy of F - F in \[{{F}_{2}}\] molecule
C) Oxygen and xenon have almost similar ionization potentials.
D) None of these.
Correct Answer: C
Solution :
Oxygen and Xenon have almost similar ionization potential and size. Prompted by this and the reaction of \[{{O}_{2}}\] and\[Pt{{F}_{6}}\] \[{{O}_{2}}+Pt{{F}_{6}}\to {{O}_{2}}^{+}{{\left[ Pt{{F}_{6}} \right]}^{-}}\] Banlen prepared the first noble gas compound by the reaction. \[Xe+Pt{{F}_{6}}\to X{{e}^{+}}{{\left[ Pt{{F}_{6}} \right]}^{-}}\]
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