A) HOCI
B) \[HCI{{O}_{2}}\]
C) \[HCI{{O}_{3}}\] and \[HCI{{O}_{4}}\]
D) \[HCI{{O}_{2}}\] and \[HCI{{O}_{3}}\].
Correct Answer: A
Solution :
\[C{{l}_{2}}O+{{H}_{2}}O\to 2HOCl\] Thus, \[C{{l}_{2}}O\] is an anhydride of HOCl.
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