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12th Class Chemistry The Solid State / ठोस प्रावस्था Question Bank Case Based (MCQs) - Solid State

  • question_answer
    NaCI was doped with \[{{10}^{-3}}\] mol % \[SrC{{l}_{2}}\]. The concentration of the cation vacancies is

    A) \[6.02\times {{10}^{18}}\text{ }mo{{l}^{-1}}\]

    B) \[6.02\times {{10}^{15}}\text{ }mo{{l}^{-1}}\]

    C) \[6.02\times {{10}^{21}}\text{ }mo{{l}^{-1}}\]

    D) \[6.02\times {{10}^{12}}\text{ }mo{{l}^{-1}}\]

    Correct Answer: A

    Solution :

    Each \[S{{r}^{2+}}\] ion introduces one cationic vacancy, therefore, number of cationic vacancies = \[{{10}^{-3}}\] mole % \[=\frac{{{10}^{-3}}}{100}\times 6.02\times {{10}^{23}}\,mo{{l}^{-1}}\] \[=\text{ }6.02\times {{10}^{18}}\text{ }mo{{l}^{-1}}\]


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