A) 144
B) 128
C) 288
D) 272
Correct Answer: C
Solution :
Sol. Using prime factorisation, |
\[32=2\times 2\times 2\times 2\times 2={{2}^{5}}\] |
and \[36=2\times 2\times 3\times 3={{2}^{2}}\times {{3}^{2}}\] |
\[\therefore \] Minimum number of books \[LCM(32,36)\] |
= Product of the greatest power of each prime factor in the numbers. |
\[={{2}^{5}}\times {{3}^{2}}=32\times 9=288\] |
So, option [c] is correct. |
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