A) 45
B) 40
C) 10
D) 35
Correct Answer: C
Solution :
Sol. \[\therefore \] By prime factorisation. |
\[420={{2}^{2}}\times 3\times 5\times 7\]and \[130=2\times 5\times 13\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,HCF\,\,(420,130)=2\times 5\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,HCF\,\,(420,130)\] is 10. |
So, option [c] is correct. |
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