10th Class Mathematics Real Numbers Question Bank Case Based MCQs - Real Number

  • question_answer
    Given that HCF (306, 657) = 9, find LCM (306, 657).

    A) 33228

    B) 22833

    C) 22338

    D) None of these

    Correct Answer: C

    Solution :

    Here, HCF of 306 and 657 = 9, we have
    \[LCM\times HCF\]= Product of the numbers
    \[\therefore \,\,\,LCM\times 9=306\times 657\]
    \[\Rightarrow LCM=\frac{306\times 657}{9}=34\times 657\]
                            = 22338
     =22338 Thus, LCM of 306 and 657 is 22338.
     


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