A) ab
B) \[{{a}^{2}}{{b}^{2}}\]
C) \[{{a}^{3}}{{b}^{2}}\]
D) \[{{a}^{3}}{{b}^{3}}\]
Correct Answer: B
Solution :
Given, \[p=a{{b}^{2}}\] and \[q={{a}^{2}}b\] |
LCM (p, q) = Product of the greatest power of each prime factor involved in the numbers, with highest power |
\[={{a}^{2}}\times {{b}^{2}}\] |
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