A) 2/3
B) 1/3
C) -2/3
D) -1/3
Correct Answer: C
Solution :
Given, \[q\left( x \right)=k{{x}^{2}}+2x+3k\] |
Sum of zeroes = equal to their product |
\[\frac{-2}{k}=\frac{3k}{k}\] |
\[k=-2/3\] |
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