A) 3/10
B) 1/3
C) 1/4
D) 1/5
Correct Answer: A
Solution :
Given, \[{{x}^{2}}+3x-10\] |
\[\alpha +\beta =-3,\,\alpha \,.\,\beta =-10\] |
\[\frac{1}{\alpha }+\frac{1}{\beta }=\frac{\alpha +\beta }{\alpha \,.\,\beta }\] |
\[=\frac{-3}{-10}=\frac{3}{10}\] |
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