A) infinitely many solutions
B) no solution
C) unique solution
D) None of the above
Correct Answer: C
Solution :
| Here, \[{{a}_{1}}=2,\,{{b}_{1}}=3,\,{{c}_{1}}=-46\] and \[{{a}_{2}}=3,\,{{b}_{2}}=5,\,{{c}_{2}}=-74\] |
| \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{2}{3},\,\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{3}{5},\,\frac{{{c}_{1}}}{{{c}_{2}}}=\frac{-46}{-74}=\frac{23}{37}\] |
| \[\frac{{{a}_{1}}}{{{a}_{2}}}\ne \frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\] |
| Hence, the above pair of equation has unique solution. |
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