A) \[(-3,0)\] and \[(4,0)\]
B) \[(-2,0)\] and \[(5,0)\]
C) \[(-1,0)\] and \[(6,0)\]
D) \[(2,0)\] and \[(4,0)\]
Correct Answer: B
Solution :
On x-axis \[y=0\]. |
So. substituting \[y=0\] in the equations \[2x-3y+4=0\] and \[x+2y-5=0,\] we get |
\[2x-3(0)+4=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2x+4=0\,\Rightarrow x=-2\] |
and \[x+2(0)-5=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x-5=0\Rightarrow \,\,x=5\] |
Hence, the given system of equations will intersect x-axis at points \[(-2,0)\] and \[(5,0),\] respectively. |
So. option [b] is correct. |
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