A) 4 sq. units
B) 6 sq. units
C) 8 sq. units
D) 12 sq. units
Correct Answer: D
Solution :
Let us plot the graph of the lines given by the equations | ||||||||
\[4x-3y=-4\] and \[4x+3y=20.\]. | ||||||||
For equation \[4x-3y=-4\] | ||||||||
| ||||||||
For equation \[4x+3y=20\] | ||||||||
| ||||||||
Plotting these points on the same graph paper, we get the following graph: | ||||||||
The vertices of the triangle formed by the two lines and the x-axis are \[(-1,0),\,\,(2,4)\] and \[(5,0)\]. | ||||||||
Area of triangle formed by the two lines and the X-axis is shaded and given by | ||||||||
\[\frac{1}{2}\times AQ\times h=\frac{1}{2}\times 6\times 4=12\,sq.\,units\] | ||||||||
So option [d] is correct. |
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