Refer situation 2 |
What will a person have to pay for travelling a distance of 30 km? |
A) Rs 185
B) Rs 289
C) Rs 275
D) Rs 305
Correct Answer: B
Solution :
As per the situation 2, the pair of linear is |
x+8y=91 ...(i) |
and \[x+14y=145\] ...(ii) |
On solving Eqs. (i) 4and (ii), we get |
\[\Rightarrow \,\,\,\,y=9\] |
Put y = 9 in Eq. (i), we get |
\[x+8\times 9=91\] |
\[\Rightarrow \,\,\,\,x=91-72=19\] |
To travel a distance of 30 km, a person has to pay amount |
\[=\text{ }x\text{ }+\text{ }30\times y\] |
\[=19+30\times 9\] |
=19+270 |
= Rs 289 |
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