A) Rs.2and Rs.4
B) Rs.4 and Rs.2
C) Rs.8 and Rs.2
D) Rs.6 and Rs.3
Correct Answer: A
Solution :
Solving the equations \[4x-3y=-4\] and \[4x+3y=20\] by the method of elimination by substitution: |
From eq. (1): \[4x=3y-4\] ...(3) |
Substituting in eq. (2), |
\[(3y-4)+3y=20\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\,6y-4=20\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,6y=24\,\,\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\,\,\,\,y=4\] |
Substituting \[y=4\] in eq. (3), |
\[4x=3\times 4-4=8\] or \[x=2\] |
Therefore, cost of one ring game \[=Rs.2\] and cost of one balloon game \[=Rs.4\]. |
So, option [a] is correct. |
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