| Directions : (41-45) |
| Motion of Charged Particle Inside Magnetic Filed |
| A charged particle moving in a magnetic field experiences a force that is proportional to the strength of the magnetic field, the component of the velocity that is perpendicular to the magnetic field and the charge of the particle. |
| This force is given by \[\overrightarrow{F}=q\left( \overrightarrow{v}\times \overrightarrow{B} \right)\] where q is the electric charge of the particle, v is the instantaneous velocity of the particle, and B is the magnetic field (in tesla). |
| The direction of force is determined by the rules of cross product of two vectors. |
| Force is perpendicular to both velocity and magngetic field. |
| Its directin is same as \[\overrightarrow{v}\times \overrightarrow{B}\] if q is positive and opposite of \[\overrightarrow{v}\times \overrightarrow{B}\] if q is negative. |
| The force is always perpendicular to both the velocity of the particle and the magnetic field that created it. Because the magnetic force is always perpendicular to the motion, the magnetic field can do not work on an isolated charge. It can only do work indirectly, via the electric field generated by a changing magnetic field. |
 |
A) remains stationary
B) spins about its own axis
C) moves in the direction of the field
D) moves perpendicular to the direction of the field.
Correct Answer: A
Solution :
For stationary electron, \[\overrightarrow{v}=0\] \[\therefore \]Force on the electron is \[{{\overrightarrow{F}}_{m}}=-e\left( \overrightarrow{v}\times \overrightarrow{B} \right)=0\]
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