A) straight line
B) circular
C) helical
D) zig-zag
Correct Answer: C
Solution :
If the charged particle has a velocity not perpendicular to \[\overrightarrow{B}\], then component of velocity along \[\overrightarrow{B}\]remains unchanged as the motion along the \[\overrightarrow{B}\] will not be affected by \[\overrightarrow{B}\] . Then, the motion of the particle in a plane perpendicular to \[\overrightarrow{B}\] as before circular one. Thereby, producing helical moiton.
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