12th Class Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Case Based (MCQs) - Moving Charges and Magnetism

  • question_answer
    Radius of particle in second magnetic field \[{{B}_{0}}\] is

    A) \[\frac{2mv}{q{{E}_{0}}}\]

    B) \[\frac{mv}{q{{E}_{0}}}\]

    C) \[\frac{mv}{q{{B}_{0}}}\]

    D) \[\frac{2m{{E}_{0}}v}{q{{B}_{0}}}\]

    Correct Answer: C

    Solution :

    As \[\frac{m{{v}^{2}}}{r}=qv\,{{B}_{0}}\,\,\,\therefore r=\frac{mv}{q{{B}_{0}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner