A) \[\frac{m}{qB}\]
B) \[\frac{qB}{2\pi m}\]
C) \[\frac{2\pi R}{v\,\cos \theta }\]
D) \[\frac{2\pi R}{v\,\sin \theta }\]
Correct Answer: B
Solution :
Period of revolution \[T=\frac{2\pi R}{v\,\sin \theta }\Rightarrow T=\frac{2\pi \left( \frac{mv\,\sin \theta }{qB} \right)}{v\,\sin \theta }\] \[\Rightarrow \,T=\frac{2\pi m}{qB}\] \[\therefore \]Frequency \[v=\frac{1}{T}=\frac{qB}{2\pi m}\]
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