| Direction: Q.11 to Q.15 |
| An electron with speed \[{{v}_{0}}<<c\]moves in a circle of radius \[{{r}_{0}}\] in a uniform magnetic field, |
 |
| This electron is able to traverse a circular path as magnetic field is perpendicular to the velocity of the electron. A force acts on the particle perpendicular to both \[\overrightarrow{{{v}_{0}}}\] and \[\overrightarrow{B}\]. This force continuously deflects the particle sideways without changing its speed and the particle will move along a circle perpendicular to the field. The time required for one revolution of the electron is \[{{T}_{0}}\] . |
| Read the given passage carefully and give the answer of the following questions. |
A) \[4{{r}_{0}}\]
B) \[2{{r}_{0}}\]
C) \[{{r}_{0}}\]
D) \[{{r}_{0}}/2\]
Correct Answer: B
Solution :
(b) \[2{{r}_{0}}\] As, \[{{r}_{0}}=\frac{mv}{qB}\Rightarrow r'=\frac{m(2{{v}_{0}})}{qB}=2{{r}_{0}}\]
You need to login to perform this action.
You will be redirected in
3 sec
