A) \[5m{{s}^{-2}}\]
B) \[1km{{s}^{-2}}\]
C) \[216m{{s}^{-2}}\]
D) \[216km{{h}^{-2}}\]
Correct Answer: D
Solution :
| [d] Given, \[{{v}_{1}}\]= 18 km/h, \[{{v}_{2}}\]= 36 km/h |
| and \[t=5=min\frac{5}{60}\operatorname{h}\ =\frac{1}{12}\operatorname{h}\] |
| \[\therefore \operatorname{Acceleration},a\frac{{{v}_{2}}-{{v}_{1}}}{t}\] |
| \[=\frac{36-18}{1/12}\] = 216 \[{{\operatorname{kmh}}^{-2}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
