A) \[\frac{17}{8}\]
B) \[\frac{8}{5}\]
C) \[\frac{6}{5}\]
D) \[\frac{8}{17}\]
Correct Answer: B
Solution :
| \[\cos ecB=\frac{BP}{PQ}=\frac{\sqrt{{{\left( 3 \right)}^{2}}+{{\left( 2.5 \right)}^{2}}}}{2.5}\] |
| \[\frac{\sqrt{9+6.25}}{25}=\frac{4}{25}\times 10\] (approx) |
| \[\cos ecB=\frac{8}{5}\] |
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