A) 1
B) 2
C) \[\frac{4}{3}\]
D) \[\frac{5}{3}\]
Correct Answer: B
Solution :
| \[\sec A=\frac{AP}{AQ}=\frac{\sqrt{A{{Q}^{2}}+P{{Q}^{2}}}}{AQ}\] |
| \[=\frac{\sqrt{{{\left( 1.5 \right)}^{2}}+{{\left( 2.5 \right)}^{2}}}}{1.5}\] |
| \[\sec A=\frac{\sqrt{2.25+6.25}}{1.5}=\frac{\sqrt{8.5}}{1.5}=\frac{3}{1.5}\] (approx) |
| \[\sec A=\frac{3}{15}\times 10=2\] |
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