A) \[\frac{8}{17}\]
B) \[\frac{15}{17}\]
C) \[\frac{17}{8}\]
D) \[\frac{17}{15}\]
Correct Answer: C
Solution :
| \[\cos ec\,\,P=\frac{\text{Hypotenuse}}{\text{Side opposite to angle P}}=\frac{PR}{QR}=\frac{17}{8}\] |
| So, option [c] is correct. |
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