A) \[30{}^\circ \]
B) \[60{}^\circ \]
C) \[45{}^\circ \]
D) None of these
Correct Answer: C
Solution :
| In \[\Delta ABD,\] \[\sin A=\frac{BD}{AB}=\frac{6}{6\sqrt{2}}=\frac{1}{\sqrt{2}}\] [Using eq. (1)] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\sin A=\sin 45{}^\circ \,\,\,\,\,\,\Rightarrow \,\,\,\,\angle A=45{}^\circ \] |
| So, option [c] is correct. |
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