A) 0
B) 1
C) -1
D) 2
Correct Answer: B
Solution :
\[{{\sin }^{2}}\theta +{{\cos }^{2}}\theta ={{\left( \frac{PR}{PQ} \right)}^{2}}+{{\left( \frac{QR}{PQ} \right)}^{2}}\] |
\[={{\left( \frac{9}{15} \right)}^{2}}+{{\left( \frac{18}{15} \right)}^{2}}=\frac{81+144}{225}=\frac{225}{225}=1\] |
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