A) 200V
B) 250V
C) 300V
D) 350V
Correct Answer: B
Solution :
Here L = 10 henry \[{{U}_{1}}=9\,A,\,{{T}_{2}}=4\,A\] and \[\Delta t=0\,.2\] second Then induced e.m.f. \[{{\varepsilon }_{1}}=L\frac{dI}{dt}=-L\frac{\left( {{I}_{2}}-{{I}_{1}} \right)}{\Delta t}=\frac{-10\times \left( 4-9 \right)}{0\,.\,2}\] \[=\frac{50}{0\,.\,2}=250\,V\].
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