A) \[0\centerdot 5\,Wb\]
B) \[12\centerdot 5\,Wb\]
C) zero
D) 2 Wb
Correct Answer: B
Solution :
Here, \[I=2\,.\,5\,A,\,L=5\,H\] Magnetic flux linked with the coil is \[{{\phi }_{B}}=LI=\left( 5H \right)\left( 2\,.\,5\,A \right)\] \[=12\,.\,5\,Wb\].
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