A) \[0\centerdot 2J\]
B) \[0\centerdot 6J\]
C) \[1\centerdot 2J\]
D) \[2\centerdot 4J\]
Correct Answer: B
Solution :
Here \[r=18\,cm\,=18\times {{10}^{-2}}\,m\], \[q=5\times {{10}^{-6}}C\] As \[C=4\pi {{\varepsilon }_{0}}r=\frac{18\times {{10}^{-2}}}{9\times {{10}^{9}}}=2\times {{10}^{-11}}F\] Energy of charged conductor is \[U=\frac{{{q}^{2}}}{2C}=\frac{{{\left( 5\times {{10}^{-6}} \right)}^{2}}}{2\times 2\times {{10}^{-11}}}=0\,.\,625\,J\]
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