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12th Class Physics Electrostatics & Capacitance Question Bank Case Based (MCQs) - Electric Potential and Capacitance

  • question_answer
    A parallel plate capacitor 1 pF has separation between the plates is d. When the distance of separation becomes 2d and wax of dielectric constant x is inserted in it, the capacitance becomes 2 pF. What is the value of x ?

    A) 2

    B) 4

    C) 6

    D) 8

    Correct Answer: B

    Solution :

    \[C=\frac{{{\varepsilon }_{0}}A}{d}=1\,pF\]                              … (i) \[C'=\frac{x{{\varepsilon }_{0}}A}{\left( 2d \right)}=2\,pF\]                                  … (ii) Divide (ii) by (i), \[x/2\text{ }=\text{ }2/1\] \[\Rightarrow \,\,x=4\]


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