| Directions: (31-35) |
| Parallel Plate Capacitor |
| The simplest and the most widely used capacitor is the parallel plate capacitor. It consists of two large plane parallel conducting plates, separated by a small distance. |
| In the outer regions above the upper plate and below the lower plate, the electric fields due to the two charged plates cancel out. The net field is zero. |
| In the inner region between the two capacitor plates, the electric fields due to the two charged plates add up. The net field is \[\frac{\sigma }{{{\varepsilon }_{0}}}\]. |
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| For a uniform electric field, potential difference between the plates = Electric field \[\times \] distance between the plates. |
| Capacitance of the parallel plate capacitor is, the charge required to be supplied to either of the conductors of the capacitor so as to increase the potential difference between them by unit amount. |
A) Charge remains constant, potential decreases & capacitance increases
B) Charge remains constant, potential increases & Capacitance decreases
C) Charge increases, potential increases & Capacitance decreases
D) Charge decreases, potential decreases & Capacitance increases.
Correct Answer: B
Solution :
As the capacitor is isolated after charging, charge Q on it remains constant. Plate separation d increases, capacitance decreases as \[C=\frac{{{\varepsilon }_{0}}A}{d}\]and hence, potential increases as\[V=\frac{Q}{C}\].
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