A) \[1.9\times {{10}^{5}}\,N{{m}^{2}}/C\]entering the surface
B) \[1.9\times {{10}^{5}}\,N{{m}^{2}}/C\] leaving the surface
C) \[~2.0\text{ }\times \text{ }{{10}^{5}}\text{ }N{{m}^{2}}/C\] leaving the surface
D) \[2.0\text{ }\times \text{ }{{10}^{5}}\text{ }N{{m}^{2}}/C\]entering the surface
Correct Answer: B
Solution :
(b) \[1.9\times {{10}^{5}}\,N{{m}^{2}}/C\] leaving the surface
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