A) \[\left[ M{{L}^{-3}}{{T}^{4}}{{A}^{2}} \right]\]
B) \[\left[ {{M}^{-1}}{{L}^{3}}{{T}^{2}}{{A}^{2}} \right]\]
C) \[\left[ {{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}} \right]\]
D) \[\left[ M{{L}^{-3}}{{T}^{4}}{{A}^{-2}} \right]\]
Correct Answer: C
Solution :
(c) \[\left[ {{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}} \right]\] As, \[\left[ {{\varepsilon }_{0}} \right]=\frac{1}{4\pi F}.\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}=\frac{{{\left[ AT \right]}^{2}}}{\left[ ML{{T}^{-2}} \right]\left[ {{L}^{2}} \right]}\] \[=\left[ {{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}} \right]\]
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