12th Class Physics Electric Charges and Fields Question Bank Case Based (MCQs) - Electric Charges and Fields

  • question_answer
    Direction Q.11 to 15
    Coulomb's law states that the electrostatic force of attraction or repulsion acting between two stationary points charges is given by
    \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\]
    where F denotes the force between two charges \[{{q}_{1}}\]and \[{{q}_{2}}\] separated by a distance r in free space, e q is a constant known as permittivity of free space. Free space is vacuum and may be taken to be air practically.
    If free space is replaced by a medium, then E o is replaced by \[\left( {{\varepsilon }_{0}}k \right)\]or \[\left( {{\varepsilon }_{0}}{{\varepsilon }_{r}} \right)\]where k is known as dielectric constant or relative permittivity.
    Read the above passage carefully and give the answer of the following questions.
    In Coulomb's law, \[F=k\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\], then on which of the following factors does the proportionality constant k depends?

    A) Electrostatic force acting between the two charges

    B) Nature of the medium between the two charges

    C) Magnitude of the two charges

    D) Distance between the two charges

    Correct Answer: B

    Solution :

    (b) Nature of the medium between the two charges The proportionality constant k depends on the nature of the medium between the two charges.


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