12th Class Physics Electric Charges and Fields Question Bank Case Based (MCQs) - Electric Charges and Fields

  • question_answer
    Directions: (21-25)
    Millikan's Oil-Drop Experiment
    In 1909, Robert Millikan was the first to find the charge of an electron in his now-famous oil-drop experiment. In that experiment, tiny oil drops were sprayed into a uniform electric field between a horizontal pair of oppositely charged plates. The drops were observed with a magnifying eyepiece, and the electric field was adjusted so that the upward force on some negatively charged oil drops was just sufficient to balance the downward force of gravity. That is, when suspended, upward force qE just equaled Mg. Millikan accurately measured the charges on many oil drops and found the values to be whole number multiples of \[1.6\times {{10}^{-19}}\text{ }C\] the charge of the electron. For this, he won the Nobel prize.
    If a drop of mass \[1\centerdot 08\times {{10}^{-14}}kg\] remains stationary in an electric field of \[1\centerdot 68\times {{10}^{5}}N{{C}^{-1}}\], then the charge of this drop is

    A) \[6\centerdot 40\times {{10}^{-19}}C\]

    B) \[3\centerdot 2\times {{10}^{-19}}C\]

    C) \[1\centerdot 6\times {{10}^{-19}}C\]

    D) \[4\centerdot 8\times {{10}^{-19}}C.\]

    Correct Answer: A

    Solution :

    As, \[qE=mg\Rightarrow q=\frac{1.08\times {{10}^{-14}}\times 9\,.\,8}{1\,.\,68\times {{10}^{5}}}\] \[=6\,.\,4\times {{10}^{-19}}C\]


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