A) \[{{S}_{1}}\] and \[{{S}_{3}}\]
B) \[{{S}_{5}}\]and \[{{S}_{6}}\]
C) \[{{S}_{2}}\] and \[{{S}_{4}}\]
D) \[{{S}_{1}}\]and \[{{S}_{2}}\]
Correct Answer: C
Solution :
Here, \[{{\hat{n}}_{{{S}_{2}}}}=+\hat{k}\] (Top) \[\therefore \,\,{{\phi }_{{{S}_{2}}}}=-\left( 4\times {{10}^{3}}\,N{{C}^{-1}} \right)\,{{\left( 0\,.\,1\,m \right)}^{2}}\,\cos \,90{}^\circ =0\] \[{{\hat{n}}_{{{S}_{3}}}}=+\hat{j}\] (Right) \[{{\hat{n}}_{{{S}_{4}}}}=+\hat{k}\](Bottom) \[\therefore \,\,{{\phi }_{{{S}_{4}}}}=\left( 4\times {{10}^{3}}\,N\,{{C}^{-1}} \right)\,{{\left( 0\,.\,1\,m \right)}^{3}}\cos \,90{}^\circ =0\]. And, \[{{\hat{n}}_{{{S}_{5}}}}=+\,\hat{i}\](Front) \[\therefore \,\,{{\phi }_{{{S}_{5}}}}=+\left( 4\times {{10}^{3}}N\,{{C}^{-1}} \right){{\left( 0\,.\,1\,m \right)}^{2}}\,\cos \,37{}^\circ \] \[=32\,N\,{{m}^{2}}\,{{C}^{-1}}\] \[{{S}_{2}}\] and \[{{S}_{4}}\]surface have zero flux.
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