12th Class Physics Electric Charges and Fields Question Bank Case Based (MCQs) - Electric Charges and Fields

  • question_answer
    Directions : (1-5)        
    Coulomb's Low
    Coulomb's law states that the electrostatic force of attraction or repulsion acting between two stationary point charges is given by
    \[F=\frac{1}{4\pi {{\in }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\]
    where F denotes the force between two charges \[{{q}_{1}}\] and \[{{q}_{2}}\]separated by a distance r in free space, eq is a constant known as perimittivity of free space. Free space is vaccum and may be taken to be air practically.
    If free space is replaced by a medium, then \[{{\varepsilon }_{0}}\]is replaced by \[\left( {{\varepsilon }_{0}}k \right)\] or \[\left( {{\varepsilon }_{0}}{{\varepsilon }_{r}} \right)\]where k is known as dielectric constant or relative perimittivity.
    In coulomb's law, \[F=\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\]then on which of the following factors does the proportionality constant k depends ?

    A) Electrostatic force acting between the two point charges

    B) Nature of the medium between the point stationary charges

    C) Magnitude of the two point charges

    D) Distance between the two point charges.

    Correct Answer: B

    Solution :

    The proportionality constant k depends on the nature of the medium between the two charges.


You need to login to perform this action.
You will be redirected in 3 sec spinner