A) \[3\]
B) \[3/2\]
C) \[2\]
D) \[1/2\]
Correct Answer: B
Solution :
By suing internal section formula. |
\[\therefore \] Coordinates of \[D=\left\{ \frac{3k+(-2)}{k+1},\frac{4k+4}{k+1} \right\}\] |
\[\Rightarrow \,\,\,\,\,(1,4)=\left\{ \frac{3k-2}{k+1},\frac{4k+4}{k+1} \right\}\] |
On comparing x-coordinate both sides, |
\[1=\frac{3k-2}{k+1}\Rightarrow 3k-2=k+1\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2k=3\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,k=\frac{3}{2}\] |
So, option [b] is correct. |
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