A) (1,6)
B) (6,1)
C) \[\left( \frac{11}{2},\,0 \right)\]
D) None of these
Correct Answer: D
Solution :
Given, coordinates of P(6, - 2) and R (10,6). |
mid-point of |
\[PR=\left( \frac{6+10}{2},\frac{-2+6}{2} \right)\] |
\[=\left( \frac{16}{2},\,\frac{4}{2} \right)=\left( 8,2 \right)\] |
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