A) zero
B) \[10\centerdot 42W\]
C) \[17\centerdot 42W\]
D) 15 W
Correct Answer: A
Solution :
\[{{P}_{C}}={{E}_{v}}{{I}_{v}}\,\cos \phi \] In a capacitor, phase difference, \[\phi =90{}^\circ \] \[\therefore \,\,{{P}_{L}}={{E}_{v}}{{I}_{v}}\,\cos 90{}^\circ =zero\]
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