12th Class Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Case Based (MCQs) - Alternating Current

  • question_answer
    Directions : (26-30)
    Resonant Series LCR Circuit
    When the frequency of ac supply is such that the inductive reactance and capacitive reactance become equal, the impedance of the series LCR circuit is equal to the ohmic resistance in the circuit. Such a series LCR circuit is known as resonant series LCR circuit and the frequency of the ac supply is known as resonant frequency.
    Resonance phenomenon is exhibited by a circuit only if both L and C are present in the circuit. We cannot have resonance in a RL or RC circuit.              
    A series LCR circuit with \[L=0\centerdot 12\,H\], C = 480 nF,
    \[R=23\,\Omega \] is connected to a 230 V variable frequency supply.
    Find the value of source frequency for which current amplitude is maximum

    A) \[222\centerdot 32\,Hz\]

    B) \[550\centerdot 52\,Hz\]

    C) \[663\centerdot 48\,Hz\]

    D) 770 Hz.

    Correct Answer: C

    Solution :

    Here, \[L=0.12\,H\], \[C=480\,nF=480\times {{10}^{-9}}F\] \[R=23\Omega \], \[V=230\,V\] \[{{V}_{0}}=\sqrt{2}\times 230\,V=325\,.\,22V\] \[{{I}_{0}}=\frac{{{V}_{0}}}{\sqrt{{{R}^{2}}+{{\left( \omega L-\frac{1}{\omega C} \right)}^{2}}}}\] At resonance, \[\omega L-\frac{1}{\omega C}=0\] \[\omega =\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.12\times 480\times {{10}^{9}}}}=4166.67\,rad\,{{s}^{-1}}\] \[{{v}_{R}}=\frac{4166.67}{2\times 3.14}=663.48\,Hz\]


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