A) Copper loss
B) Stray lose
C) Dielectric loss
D) Core loss
Correct Answer: A
Solution :
| Option [a] is correct. |
| Explanation: If the currents in primary and secondary windings of the transformer are \[{{I}_{1}}\] and \[{{I}_{2}}\] respectively and the resistances of theses winding are \[{{\operatorname{R}}_{1}}\] and \[{{\operatorname{R}}_{2}}\] then the copper losses that occurred in the windings are \[{{I}_{1}}^{2}{{\operatorname{R}}_{1}}\] and \[{{I}_{2}}^{2}{{\operatorname{R}}_{2}}\] respectively. So, the entire copper loss will be \[{{I}_{1}}^{2}{{\operatorname{R}}_{1}}+{{I}_{2}}^{2}{{\operatorname{R}}_{2}}\]. |
| This loss is also called variable or ohmic losses because this loss changes based on the load. |
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