| The products of the oxidation |
| \[C{{H}_{3}}CH=CHCH\left( OH \right)C{{H}_{3}}\xrightarrow[acetone]{{{H}_{2}}Cr{{O}_{4}}\,in\,aq.}\] is/are |
A) \[C{{H}_{3}}-CH=CH-CHO\]
B) \[C{{H}_{3}}-CH=CH-COC{{H}_{3}}\]
C)
D)
Correct Answer: B
Solution :
Chromic acid oxidises sec. alcohol to ketone without affecting double bond
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