| Directions: (Q. 6 to 10) |
| Case II: Read the passage given below and answer the following questions. |
| When haloalkanes with (\[\beta \]-hydrogen atom are boiled with alcoholic solution of KOH; they undergo elimination of hydrogen halide resulting in the formation of alkenes. These reactions are called (\[\beta \]-elimination reactions or dehydrohalogenation reactions. These reactions follow Saytzeff's rule. Substitution and therefore can engage in substitution or elimination reactions depending upon the alkyl halide and the reaction conditions. |
A) \[C{{H}_{2}}=CHBr\]
B) \[C{{H}_{3}}COC{{H}_{2}}C{{H}_{2}}Br\]
C) \[C{{H}_{3}}C{{H}_{2}}Br\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]
Correct Answer: D
Solution :
In alkyl halides, polarity of C - Br bond increases with increase in chain length.
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