A) \[3{}^\circ <2{}^\circ <\text{ }1{}^\circ \]
B) \[3{}^\circ >2{}^\circ >\text{ }1{}^\circ \]
C) \[3{}^\circ <2{}^\circ >\text{ }1{}^\circ \]
D) \[3{}^\circ >2{}^\circ \text{ }<\text{ }1{}^\circ \]
Correct Answer: B
Solution :
The ease of dehydrohalogenation of alkyl halide with alcoholic KOH is \[3{}^\circ \text{ }>\text{ }2{}^\circ \text{ }>\text{ }1{}^\circ \]. This order of alkyl halides can be explained on the basis of the stability of the alkene formed after dehydrohalogenation of natoalkanes. \[3{}^\circ \] alkyl halides on dehydrohalogenation forms more substituted alkenes, which being more stable and formed at faster rate, while primary alkyl halides yield least substituted alkenes, which being less stable and formed at slower rate.
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