1. Ethyl propanoate |
2. PropyI methanoate |
3. Methyl butanoate |
4. Ethyl butanoate |
A) 1 only
B) 4 only
C) 1 and 3 only
D) 1 and 2 only.
Correct Answer: C
Solution :
Ethyl propanoate :\[\underset{(10\,H\,atoms)}{\mathop{C{{H}_{3}}C{{H}_{2}}COOC{{H}_{2}}C{{H}_{3}}}}\,\] PropyI methanoate : \[\underset{(8\,H\,atoms)}{\mathop{HCOOC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\] Methyl butanoate : \[\underset{(10\,H\,atoms)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COOC{{H}_{3}}}}\,\] Ethyl butanoate : \[\underset{(12\,H\,atoms)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COOC{{H}_{2}}}}\,C{{H}_{3}}\]You need to login to perform this action.
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