A) Rotatory motion
B) Inversion
C) Specific rotation
D) Mutarotation
Correct Answer: D
Solution :
\[\underset{(36%)}{\mathop{\underset{[\alpha ]=+{{112}^{o}}}{\mathop{\alpha -D-\text{Glucose}}}\,}}\,\] ⇌ \[\underset{(0.02%)}{\mathop{\underset{{{\text{ }\!\![\!\!\text{ }\alpha \text{ }\!\!]\!\!\text{ }}_{\text{D}}}=+{{52}^{o}}}{\mathop{\text{Equilibrium mixture}}}\,}}\,\] ⇌ \[\underset{(64%)}{\mathop{\underset{{{[\alpha ]}_{D}}=+{{19}^{o}}}{\mathop{\beta -D-\text{Glucose}}}\,}}\,\] Glucose has two forms a and b. When either of these two is dissolved in water and allowed to stand, it gets converted to an equilibrium mixture of a and b forms.
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