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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Capacitance

  • question_answer
    The area of the plates of a parallel plate condenser is \[A\] and the distance between the plates is \[10mm\]. There are two dielectric sheets in it, one of dielectric constant 10 and thickness \[6mm\] and the other of dielectric constant 5 and thickness \[4mm\]. The capacity of the condenser is [MP PMT 1997]

    A)                    \[\frac{12}{35}{{\varepsilon }_{0}}A\]

    B)                                      \[\frac{2}{3}{{\varepsilon }_{0}}A\]

    C)                    \[\frac{5000}{7}{{\varepsilon }_{0}}A\]                 

    D)            \[1500\ {{\varepsilon }_{0}}A\]

    Correct Answer: C

    Solution :

               \[C=\frac{{{\varepsilon }_{0}}A}{\left( \frac{{{t}_{1}}}{{{k}_{1}}}+\frac{{{t}_{2}}}{{{k}_{2}}} \right)}=\frac{{{\varepsilon }_{0}}A}{\frac{6\times {{10}^{-3}}}{10}+\frac{4\times {{10}^{-3}}}{5}}=\frac{5000}{7}{{\varepsilon }_{0}}A\]


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