A) \[9\times {{10}^{6}}\ volts\]
B) \[4.5\times {{10}^{6}}\ volts\]
C) \[1.8\times {{10}^{7}}\ volts\]
D) \[13.5\times {{10}^{6}}\ volts\]
Correct Answer: A
Solution :
Common potential \[V=\frac{\text{Total charge }}{\text{Total capacitance}}\] \[V=\frac{150\times {{10}^{-6}}\times 2}{4\pi {{\varepsilon }_{0}}(10\times {{10}^{-2}}+20\times {{10}^{-2}})}=9\times {{10}^{6}}\,V\]
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