A) The electric intensity between the plates will decrease
B) The electric intensity between the plates will increase
C) The electric intensity between the plates will remain unchanged
D) The P.D. between the plates will decrease
Correct Answer: C
Solution :
Electric field between the plates of a parallel plate capacitor \[E=\frac{\sigma }{{{\varepsilon }_{0}}}=\frac{Q}{A{{\varepsilon }_{0}}}\] i.e. \[E\propto {{d}^{o}}\]
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